The radius of the circular path of a charged particle in a magnetic field is given by
Correct answer: B. r equals mv over qB
- A. r equals qB over mv
- B. r equals mv over qB
- C. r equals mvB over q
- D. r equals qvB
Explanation
Equating the magnetic force qvB to the required centripetal force mv squared over r and rearranging gives r equal to mv over qB. A heavier or faster particle therefore curves less, while a stronger field curves it more tightly. Because the radius depends on mass for a given charge and speed, this expression is the basis of the mass spectrometer.
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About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
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