Hard

Propanone is prepared by the oxidation of

Correct answer: C. propan-2-ol

  • A. propan-1-ol
  • B. propane
  • C. propan-2-ol
  • D. propanoic acid

Explanation

Propan-2-ol is a secondary alcohol, so removing the hydrogen from the carbinol carbon leaves a ketone, and the reaction stops there because no further hydrogen remains on that carbon. Propan-1-ol, being primary, would give propanal and then propanoic acid instead. Most propanone is actually obtained as the by product of the cumene process for phenol.

Written and checked by , M.Phil ChemistryLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? support@testustad.com

About Preparation of Aldehydes and Ketones

Aldehydes and ketones are prepared mainly by controlled oxidation or dehydrogenation of primary and secondary alcohols, respectively. The topic also includes ozonolysis of alkenes, hydration of alkynes and preparation through acyl derivatives, with attention to why primary alcohols can give aldehydes whereas secondary alcohols give ketones.

Practise Aldehydes and Ketones

679 free Aldehydes and Ketones MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Chemistry questions like this

Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Preparation of Aldehydes and Ketones questions