Ca(OH)2 is sparingly soluble having solubility constant value 6.5 x 10-6. What'll be its solubility:
Correct answer: C. 1.17 x 10^-2
- A. 2.75 x 10^-2
- B. 2.75 x 10^2
- C. 1.17 x 10^-2
- D. 3.63 x 10^3
Explanation
The solubility product constant (Ksp) expression for Ca(OH)2is: Ca(OH)2(s) ⇌ Ca2+(aq) + 2OH-(aq) The Ksp expression can be written as: Ksp = [Ca2+][OH-]^2 Given that the solubility constant value (Ksp) is 6.5 x10^-6, we can assume that x mol/L of Ca(OH)2 dissolves, leading to theformation of x mol/L of Ca2+ and 2x mol/L of OH-. Substituting these values into the Ksp expression, we get: 6.5 x 10^-6 = (x)(2x)^2 6.5 x 10^-6 = 4x^3 Dividing both sides by 4, we have: 1.625 x 10^-6 = x^3 To find x, we can take the cube root of both sides: x = (1.625 x 10^-6)^(1/3) Calculating this value gives us: x ≈ 0.0117 mol/L Therefore, the solubility of Ca(OH)2 is approximately 0.0117mol/L.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? support@testustad.com
About Solutions and Colloids
Solutions are described using molarity, molality, normality, mole fraction, percentage concentration and parts per million. Coverage also includes vapour-pressure lowering, boiling-point elevation, freezing-point depression and osmotic pressure, then distinguishes true solutions, colloids and suspensions by particle size, stability, light scattering and settling.
Practise Solutions and Colloids
119 free Solutions and Colloids MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Solutions and Colloids questions
Molal freezing point constant of water is:
If 18.0 g of glucose is dissolved in 1 kg of water, boiling point of this solution should be:
Molarity is defined as the number of moles of any substance dissolved:
The compound with more than 10% solubility in pure water is:
The elevation in boiling point ∆𝑇𝑏 is equal to ebullioscopic constant 𝐾𝑏 when the Molarity (𝑀) of the solution is:
The aqueous solution of which of the following electrolyte will conduct electric current to large extent: