A coordination complex compound of cobalt has a molecular formula containing five ammonia molecules, one nitro group, and two chlorine atoms for one cobalt atom. One mole of this compound produces three-mole ions in an aqueous solution. By the reaction of this solution with excess silver nitrate solution, two molecules of AgCl get precipitated. The ionic formula of this compound would be:
Correct answer: C. [Co(NH3)5NO2]Cl2
- A. [Co(NH3)4NO2Cl] [(NH3)Cl]
- B. [Co(NH3)5Cl] [Cl(NO2)]
- C. [Co(NH3)5NO2]Cl2
- D. [Co(NH3)5] [(NO2)2Cl2]
Explanation
Because only (C) gives two moles of AgCl with AgNO3 and yields three ions (including two ionizable Cl- ions) in an aqueous solution.[Co(NH3)5NO2]Cl2] [Co(NH3)5NO2]2+ + 2Cl-
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A complex compound of cobalt has a molecular formula containing five NH3 molecules, one nitro group and two chlorine atoms for one Co atom. One mole of this compound produces three moles of ions in an aqueous solution. On reacting with excess AgNO3 solution, two moles of AgCl get precipitated. The ionic formula of the compound is?
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