The two spherical shells are at large separation. One of them has a radius of 10 cm and has 1.25 µC charge. The other is of 20 cm radius and has a 0.75 µC charge. If they are connected by a conducting wire of negligible capacity, the charge on the shells are:

Explanation

When two conductive spherical shells are connected by a wire, they share charge until they reach the same electric potential. The potential V is given by V = kQ/R, where k is Coulomb's constant, Q is the charge, and R is the radius. Initially, the total charge is 1.25 µC + 0.75 µC = 2 µC, which is conserved. Let the charges on the smaller and larger shells be Q1 and Q2 respectively. The potential equality condition gives Q1/10 = Q2/20, and charge conservation gives Q1 + Q2 = 2. Solving these equations yields Q1 = 2/3 µC and Q2 = 4/3 µC. Therefore, Option B is correct. Other options do not satisfy the potential equality and charge conservation conditions.