The force of repulsion between two alike charges is 10 N in vacuum. When a material of Ep= 2 is placed between them. New force will be:
Correct answer: D. 5 N
- A. 20 N
- B. 15 N
- C. 10 N
- D. 5 N
Explanation
In this problem, we start with a repulsive force of 10 N between two like charges in a vacuum. When a dielectric material with an electric polarization factor of Ep= 2 is introduced, the force between the charges is reduced by this factor. The relationship governing this change is given by:F' = F / Ep,where F' is the new force, F is the original force (10 N), and Ep is the electric polarization factor (which is 2 in this case). Thus:F' = 10 N / 2 = 5 N.This shows that the force is halved due to the presence of the dielectric. The other options are incorrect as they either suggest an increase in force or no change at all, which contradicts the effect of the dielectric material on the electric forces between the charges.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
Practise Electrostatics
831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electrostatics questions
Two equal and opposite charges of 10 C are separated at a distance of 10 cm, the electric potential at mid-point between the charges is:
Ampere.second is the unit of:
1 volt x 1 ampere is equal to:
The slope-of the charge-time graph for a charging capacitor gives:
Two small charged objects attract each other with a force F when separated by a distance d. If the charge on each object is reduced to one-fourth of its original value and the distance between them is reduced to d/2 the force becomes:
If both the plate area and the plate separation of a parallel-plate capacitor doubled, the capacitance is