The force of repulsion between two alike charges is 10 N in vacuum. When a material of Ep= 2 is placed between them. New force will be:
Correct answer: D. 5 N
- A. 20 N
- B. 15 N
- C. 10 N
- D. 5 N
Explanation
In this problem, we start with a repulsive force of 10 N between two like charges in a vacuum. When a dielectric material with an electric polarization factor of Ep= 2 is introduced, the force between the charges is reduced by this factor. The relationship governing this change is given by:F' = F / Ep,where F' is the new force, F is the original force (10 N), and Ep is the electric polarization factor (which is 2 in this case). Thus:F' = 10 N / 2 = 5 N.This shows that the force is halved due to the presence of the dielectric. The other options are incorrect as they either suggest an increase in force or no change at all, which contradicts the effect of the dielectric material on the electric forces between the charges.
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