Potential due to charge q at a distance 1m is 5V. At a distance 3m will be

Explanation

We can use the formula for the electric potential due to a point charge to determine the potential at different distances:V = k * q / rwhere:V is the electric potential (in Volts)k is the Coulomb constant (approximately 8.99 x 10^9 N⋅m²/C²)q is the charge (in Coulombs)r is the distance from the point charge (in meters)We are given that the potential (V) is 5V at a distance (r) of 1 meter due to a charge (q). We need to find the potential when the distance is increased to 3 meters (new distance = 3m).Step 1: Solve for the unknown charge (q):Since we know the potential (V) and the distance (r) for the initial case, we can rearrange the formula to solve for the charge (q):q = V * r / kPlugging in the known values:q = 5V * 1m / (8.99 x 10^9 N⋅m²/C²)q ≈ 5.55 x 10^-10 CStep 2: Find the potential at the new distance (3m):Now that we know the charge (q), we can use the same formula to find the potential (V') at the new distance (r' = 3m):V' = k * q / r'V' = (8.99 x 10^9 N⋅m²/C²) * (5.55 x 10^-10 C) / 3mV' ≈ 1.85 V= 5/3VTherefore, the potential due to the charge (q) at a distance of 3 meters will be approximately 1.85 Volts.Incorrect options: (b), (c), and (d) These options don't represent the correct calculation for the potential at 3m.