Moment of inertia of a uniform circular disc about a diameter is 4I. Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be:
Correct answer: C. 6I
- A. 5I
- B. 3I
- C. 6I
- D. 4I
Explanation
This is the following solution:The correct formula for the moment of inertia of a uniform circular disc about an axis perpendicular to its plane and passing through a point on its rim is (3/2)MR2, where M is the mass of the disc and R is its radius.Therefore, the moment of inertia about the rim axis can be calculated as:I-rim = (3/2)MR2Since we are given that the moment of inertia about the diameter is I, we can substitute MR2 with 4I (as given in the problem statement).I-rim = (3/2)(4I)Simplifying the expression, we get:I-rim = 6ITherefore, the correct answer is option C: The moment of inertia of a uniform circular disc about an axis perpendicular to its plane and passing through a point on its rim is 6I.
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