If the position vector of a particle is r=(3i+4j) meter and its angular velocity is w=(j+2k) rad/sec then its linear velocity is (in m/s):
Correct answer: A. -(8i - 6j + 3k)
- A. -(8i - 6j + 3k)
- B. (3i - 6j + 8k)
- C. -(3i - 6j + 6k)
- D. (6i - 8j + 3k)
Explanation
To find the linear velocity, take the cross product of the position vector (3i+4j) and the angular velocity (j+2k). This will result in the correct linear velocity.
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Rotational motion relates angular displacement, angular velocity and angular acceleration to linear displacement, tangential velocity and tangential acceleration through the radius. Questions use radians, v equals r omega and tangential acceleration, while distinguishing tangential velocity from centripetal acceleration and angular quantities from their linear counterparts.
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