A particle moves in a circular of radius 25cm at two revolutions per second. The radial acceleration of the particle is:

Explanation

Therefore, the correct answer is option C: 4π^2. The radial acceleration of the particle is approximately 4π^2 m/s² as : The angular velocity (ω) of the particle can be calculated by converting the number of revolutions per second to radians per second: ω = 2π × number of revolutions per second. In this case, the particle completes two revolutions per second, so: ω = 2π × 2 = 4π rad/s. Now, the radial acceleration (ar) can be calculated using the formula: ar = r × ω^2, where r is the radius of the circular path. Given that the radius (r) is 25 cm, which is 0.25 m (since 1 m = 100 cm), we can calculate the radial acceleration: ar = (0.25 m) × (4π rad/s)^2 ≈ 4π^2 m/s². The calculated radial acceleration is approximately 4π^2 m/s², which matches option C.