What is the concentration of the Ag+ ion in a saturated solution of AgCl?(Ksp for AgCl = 1.7 × 10−10)

Correct answer: C. 1.3 × 10−5 M

  • A. 1.7 × 10−10 M
  • B. 3.4 × 10−10 M
  • C. 1.3 × 10−5 M
  • D. 2.6 × 10−5 M

Explanation

The solubility product constant (Ksp) for AgCl is given by the equation Ksp = [Ag+][Cl-]. In a saturated solution of AgCl, the concentration of silver ions [Ag+] is equal to the concentration of chloride ions [Cl-]. Let this common concentration be x. Therefore, Ksp = x2. Given that Ksp = 1.7 × 10−10, we solve for x by taking the square root: x = √(1.7 × 10−10) = 1.3 × 10−5 M. This means the concentration of Ag+ ions in the saturated solution is 1.3 × 10−5 M. The other options are incorrect as they either misuse the Ksp value or misinterpret the stoichiometry of the equilibrium.

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