Two different liquids are flowing in two tubes of equal radius. The ratio of coefficients of viscosity of liquids is 52:49 and the ratio of their densities is 13:1, then the ratio of their critical velocities will be
Correct answer: A. 4:49
- A. 4:49
- B. 49:4
- C. 2:7
- D. 7:2
Explanation
The critical velocity (Vc) can be calculated using the formula: Vc ∝ (η/ρ), where η is the coefficient of viscosity and ρ is the density of the fluid. Given the ratio of coefficients of viscosity as 52:49 and the ratio of densities as 13:1, we can express the ratio of critical velocities (Vc1:Vc2) as follows:Vc1:Vc2 = (η1/ρ1):(η2/ρ2) = (52/13):(49/1) = (4:49).Thus, the correct answer is Option A (4:49). Options B, C, and D do not accurately reflect the derived ratios based on the provided coefficients of viscosity and densities.
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