The solubility product constant Ca(OH)2 is 5.02 *10-5. What is the solubility of this compound?
Correct answer: C. 0.023M
- A. 0.020M
- B. 0.012M
- C. 0.023M
- D. 0.037M
Explanation
Solubility is the ability of a solute to dissolve into a solvent. It is calculated by creating an equilibrium equation and solving for the concentration of dissolved ions.For this question, we will need to set up the equilibrium constant equation for calcium hydroxide.Ca(OH)2⇌Ca2++2OH−; Ksp=[Ca2+][OH−]Note that the solid compound is not included in the equilibrium expression. Now we can work on finding solubility. For each mole of calcium hydroxide dissolved, one mole of calcium ions and two moles of hydroxide ions are released. Mathematically, we can equate this ratio to the ion concentrations in the equilibrium calculation.Ca(OH2): Ksp=5.02∗10−5=(x)(2x)2In this calculation, x is the solubility. Given the solubility constant, we can solve for x.5.02∗10−5=4x3→xCa(OH)2=0.023M
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Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
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