The refluxing of (CH3)2NCOCH3 with acid gives:
Correct answer: C. (CH3)2NH + CH3COOH
- A. 2CH3NH2 + CH3COOH
- B. 2CH3OH + CH3COOH
- C. (CH3)2NH + CH3COOH
- D. (CH3)2NCOOH + CH4
Explanation
When (CH3)2NCOCH3 is refluxed with acid, it undergoes hydrolysis to form 2(CH3)NH2 + CH3COOH. The reaction proceeds as follows: 1. The amide group of (CH3)2NCOCH3 is protonated by the acid to form a salt. 2. The salt is then heated under reflux conditions with water, which leads to the hydrolysis of the amide bond. 3. The final step is the acid-catalyzed deprotonation of the ammonium ion form 2(CH3)NH2 and CH3COOH.
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About Alkyl Halides
Alkyl halides are named and related to their carbon-halogen structure, polarity and reactivity. The key reactions are nucleophilic substitution by SN1 and SN2 mechanisms and elimination by E1 and E2 mechanisms, including how substrate structure, nucleophile, base, solvent and temperature influence substitution versus elimination.
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