The reduction potential of hydrogen half-cell will be negative if:
Correct answer: C. p(H2)=2 atm and [H+] = 1M
- A. p(H2)=1 atm and [H+]=1M
- B. p(H2)=2 atm and [H+] = 2M
- C. p(H2)=2 atm and [H+] = 1M
- D. p(H2)=1 atm and [H+]= 2M
Explanation
According to the Nernst equation, the reduction potential of a half-cell is affected by the concentration of ions and the partial pressure of gases involved. For a hydrogen half-cell, the standard reduction potential is zero at 1 atm pressure and 1M concentration of H+. Option C presents a scenario where the partial pressure of hydrogen is increased to 2 atm while maintaining the standard concentration of H+. This results in a shift in equilibrium towards oxidation, causing the reduction potential to become negative. In contrast, Option A describes standard conditions resulting in zero potential, Option B could have a balanced effect maintaining the potential near zero, and Option D increases the concentration of H+ which would increase the reduction potential, making it positive.
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Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
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