The projectile attains maximum horizontal range when it is projected at an angle of:
Correct answer: B. 45° with the horizontal
- A. 30° with the horizontal
- B. 45° with the horizontal
- C. 60° with the horizontal
- D. 90° with the horizontal
Explanation
The explanation is given below: The horizontal range of a projectile is the maximum distance it can travel horizontally. For a projectile launched at an angle θ with respect to the horizontal, the range (R) is given by the formula: R = v2sin (2θ)/g To find the angle that maximizes the range, one can take the derivative of the range equation with respect to the launch angle θ and set it equal to zero. Solving for θ will give the angle at which the range is maximized. The solution turns out to be θ = 45o which means that the maximum range is achieved when the projectile is launched at an angle of 45 degrees.
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About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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