The introduction of an alkyl group in benzene takes place in the presence of AlCl3 and the reagent is:
Correct answer: B. Option B: Alkyl halide
- A. Option A: AlCl3
- B. Option B: Alkyl halide
- C. Option C: AlCl3 and alkyl halide
- D. Option D: AlCl3 and FeCl3
Explanation
The introduction of an alkyl group in benzene occurs through Friedel-Crafts alkylation, where the alkyl halide acts as the reagent in the presence of a catalyst such as AlCl3. This reaction results in the formation of alkylbenzene and hydrogen halide. Therefore, option B, alkyl halide, is the correct answer. Option A is incorrect as AlCl3 is the catalyst, not the reagent. Option C is incorrect as it confuses the roles of AlCl3 and the alkyl halide. Option D is incorrect as FeCl3 can also be a catalyst, but it is not typically used in this specific reaction.
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Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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