The hybridization of benzene is:
Correct answer: B. sp²
- A. sp³
- B. sp²
- C. sp
- D. None of these
Explanation
As we discussed before, each carbon atom in benzene forms three sigma bonds (two with other carbon atoms and one with a hydrogen atom). This requires three hybrid orbitals for bonding. To form these three hybrid orbitals, one s orbital and two p orbitals from the carbon atom hybridize, resulting in sp<sup>2</sup> hybridization. The remaining unhybridized p orbital on each carbon atom overlaps with the p orbitals of adjacent carbon atoms to form a delocalized pi system above and below the plane of the benzene ring.
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About Chemistry of Hydrocarbons
Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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