The electric field strength between a pair of plates is "E". If the separation of the plates is doubled and the potential difference between the plates is increased by a factor of four, the new field strength is:
Correct answer: B. 2E
- A. E
- B. 2E
- C. 4E
- D. 8E
Explanation
Electric field is calculated by the formula = Voltage / Distance so doubling the separation of plates decreases the electric field by 2 times and increasing pd between plates by factor of four, increases electric field 4 times so the over all increase is 2E
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About Electric Field Intensity
Electric field intensity is the force acting per unit positive test charge, with direction set by the force on that charge. Work includes fields of point charges, vector superposition, field lines and the relation between field and electric potential. Field intensity must be distinguished from electric force and potential.
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