NH4COONH2(s)<-> 2NH3(g) + CO2(g). If equilibrium pressure is 3 atm for the above reaction; Kp will be :
Correct answer: A. 4
- A. 4
- B. 27
- C. 4/27
- D. 1/27
Explanation
To find the equilibrium constant Kp for the reaction NH4COONH2(s) <-> 2NH3(g) + CO2(g), we use the formula Kp = PNH3^2 * PCO2 where P represents the partial pressures of the gases. Given that the total equilibrium pressure is 3 atm, and considering the stoichiometry of the reaction (2:1 for NH3 to CO2), we can determine that PNH3 = 2 atm and PCO2 = 1 atm. Thus, Kp = (2)^2 * (1) = 4. The other options result from errors in calculating the partial pressures or applying the equilibrium expression.
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