Joule-Thomson co-efficient for a perfect gas is_____________________?
Correct answer: A. Zero
- A. Zero
- B. Positive
- C. Negative
- D. None of these
Explanation
A perfect gas has enthalpy independent of pressure, so its Joule-Thomson coefficient, μJT = (∂T/∂P)H, is zero. Real gases can have positive or negative values depending on temperature and pressure.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? support@testustad.com
Practise Chemical Engineering Thermodynamics
598 free Chemical Engineering Thermodynamics MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemical Engineering questions like this
Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.
More Chemical Engineering Thermodynamics questions
What is the number of degree of freedom for a system of two miscible non-reacting species in vapor-liquid equilibrium forming an azeotrope ?
What is the value of ln y (where y = activity co-efficient) for ideal gases ?
Change of heat content when one mole of compound is burnt in oxygen at constant pressure is called the__________________?
Tea kept in a thermos flask is vigorously shaken. If the tea is considered as a system, then its temperature will_________________?
The temperature at which both liquid and gas phases are identical, is called the _____________ point?
If an ideal solution is formed by mixing two pure liquids in any proportion, then the ___________________ of mixing is zero?