In Kp= KC (RT)∆n, ∆n may have

Explanation

Option D is correct.Yes, ∆n in Kp = Kc (RT) ∆n ∆n may have: 1. Positive values 2. Zero values 3. Negative values The expression for Kp, the equilibrium constant in terms of partial pressures, is: Kp = Kc(RT)^(∆n) where Kc is the equilibrium constant in terms of concentrations, R is the gas constant, T is the temperature, and ∆n is the difference between the number of moles of gas on the reactants side and the number of moles of gas on the products side. ∆n can have positive, negative, or zero values. If ∆n is positive, then there are more moles of gas on the product side than on the reactants side. In this case, Kp will be greater than Kc. If ∆n is negative, then there are more moles of gas on the reactant's side than on the product's side. In this case, Kp will be less than Kc. If ∆n is zero, then the number of moles of gas on the reactant's side and the product's side is the same. In this case, Kp will be equal to Kc.