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For the reaction N2 + O2 2NO, the value of K is 0.0842 at 3500 K. Calculate the fraction of equilibrium mixture of N2 and O2 converted into NO.

Correct answer: D. 16.9%

  • A. 15.0%
  • B. 16.3%
  • C. 16.5%
  • D. 16.9%

Explanation

To find the fraction of N2 and O2 converted into NO at equilibrium, we define x as the fraction converted. The equilibrium concentrations can be expressed as [NO] = 2x, [N2] = (1 - x), and [O2] = (1 - x). Using the equilibrium constant expression K = (2x)^2 / ((1 - x) * (1 - x)), we substitute K = 0.0842 and simplify to form a quadratic equation: 4.0842x^2 - 0.1684x - 0.0842 = 0. Solving this equation gives x ≈ 0.169, which translates to approximately 16.9%. Therefore, Option D is correct. Other options result from calculation errors or incomplete solutions, leading to incorrect fractions of conversion.

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Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.

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