For the curve y = x³ - 2x + 1, what is the equation of the normal at x = 1?

Correct answer: D. y - 2 = -(1/1)(x - 1)

  • A. y - 1 = (1/1)(x - 1)
  • B. y - 1 = -(1/1)(x - 1)
  • C. y - 2 = (1/1)(x - 1)
  • D. y - 2 = -(1/1)(x - 1)

Explanation

At x = 1, the curve has y = 0, not y = 1 or 2. Since dy/dx = 3x² - 2, the tangent slope is 1 and the normal slope is -1, so y = -x + 1, written as y - 0 = -(x - 1). The listed option d contains y - 2 and is therefore incorrect as written.

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