For any value of initial velocity, the minimum range of projectile is obtained by throwing it at an angle of:
Correct answer: A. 90° or 0°
- A. 90° or 0°
- B. 30° or 60°
- C. 40° or 50°
- D. 45°
Explanation
When a projectile is thrown at 90°, it results in a horizontal range of 0, which is the minimum value it can achieve. The formula R = v^2 (sin 2θ)/g shows that when θ is 90°, sin 2θ will be sin 180° = 0, leading to a range of 0. Therefore, throwing the projectile at 90° gives the minimum range possible. The other angles do not result in the minimum range, as explained above.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Force and Motion questions
For a given value of Vi, the maximum range of a projectile is given by:
For a given value of initial velocity, the maximum range of a projectile can be achieved by throwing it at an angle of:
The horizontal range of a projectile can be found by the formula:
The total time taken by a projectile from starting at the surface of the earth to landing again on it is given by:
The position vector of a projectile is described by:
Circular motion is an example of motion in: