For any value of initial velocity, the minimum range of projectile is obtained by throwing it at an angle of:
Correct answer: A. 90° or 0°
- A. 90° or 0°
- B. 30° or 60°
- C. 40° or 50°
- D. 45°
Explanation
When a projectile is thrown at 90°, it results in a horizontal range of 0, which is the minimum value it can achieve. The formula R = v^2 (sin 2θ)/g shows that when θ is 90°, sin 2θ will be sin 180° = 0, leading to a range of 0. Therefore, throwing the projectile at 90° gives the minimum range possible. The other angles do not result in the minimum range, as explained above.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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