A 2 kg object is projected at 20 m/s at 53° above the horizontal. What is the maximum height reached? (g = 9.8 m/s², neglect air resistance)
Correct answer: C. 13.1 m
- A. 4.8 m
- B. 6.4 m
- C. 13.1 m
- D. 10.2 m
Explanation
To find the maximum height, we first resolve the initial velocity into its vertical component using vy = v sin 53°. Since sin 53° ~ 0.8, the vertical velocity becomes vy= 20 x 0.8 = 16 m/s. The maximum height of a projectile is given by H = vy2/ 2g . Substituting the values, we get H = 162/ 2 x 9.8 = 256/19.6 ~ 13.1 m. Thus, the object rises to a maximum height of about 13.1 m.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Force and Motion questions
A 5 kg block on a frictionless incline at 30° is pulled by a rope parallel to the incline with a force of 50 N. What is the acceleration of the block? (g = 9.8 m/s²)
The displacement of particles as a function of time is shown in the figure. The figure shows:
The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The distance travelled by the particle in four seconds is :
Equations of kinetics are valid only when the acceleration is:
Two objects, m₁ = 3 kg and m₂ = 5 kg, collide elastically in one dimension. If m₁ moves at 4 m/s and m₂ is at rest, what is the velocity of m₁ after collision?
What force should be applied on a 10 kg body so that it moves down in a vacuum with an acceleration of 3 m/s2 ? (Take g=9.8 m/s2)