Free Acids, Bases and Salts MCQs with Answers

290 Acids, Bases and Salts MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

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290 questions · page 5 of 29

41. Which of the following salts gives a neutral solution?

  • A. NaCl
  • B. NaNO₃
  • C. KI
  • D. All of the above

Explanation: All three salts listed (NaCl, NaNO₃, KI) are formed from the reaction of a strong acid and a strong base. The ions of these salts do not hydrolyze water, so their aqueous solutions are neutral.

Correct answer: All of the above

42. Which of the following aqueous solutions will be basic?

  • A. NaCl
  • B. Na₂CO₃
  • C. Na₂SO₄
  • D. FeCl₃

Explanation: Sodium carbonate (Na₂CO₃) is the salt of a weak acid (H₂CO₃) and a strong base (NaOH). The carbonate ion (CO₃²⁻) hydrolyzes water to produce OH⁻ ions, making the solution basic.

Correct answer: Na₂CO₃

43. The pH of 10-2 M aqueous solution of sodium hydroxide is:

  • A. 14
  • B. 10
  • C. 12
  • D. 13

Explanation: A 10⁻² M NaOH solution has [𝑂𝐻−]=10 −2 So, pOH = 2, and pH = 14 − 2 = 12. Thus, the solution is strongly basic.

Correct answer: 12

44. Strong acid can be involved in a spontaneous reaction which is termed as:

  • A. Addition reaction
  • B. Substitution reaction
  • C. Neutralization reaction
  • D. Reversible reaction

Explanation: A strong acid reacts spontaneously with a strong base. This process produces salt and water and releases energy. Such a spontaneous reaction is called a neutralization reaction.

Correct answer: Neutralization reaction

45. The pKa value of acetic acid is:

  • A. 1.34
  • B. 3.52
  • C. 4.76
  • D. 2.53

Explanation: The pK of an acid indicates its strength; lower pK means stronger acid. For acetic acid (CH₃COOH), the pKa is experimentally determined to be 4.76. a a This reflects that acetic acid is a weak acid.

Correct answer: 4.76

46. 'Ka ' for an acid is higher, the stronger is the acid; relate the strength of an acid with 'pKa ' :

  • A. Higher pKa , weaker the acid
  • B. Lower pKa , stronger the acid
  • C. pKa has no relation with acid strength
  • D. Both "Higher pKa , weaker the acid" & "Lower pKa , stronger the acid"

Explanation: The acid dissociation constant Ka measures acid strength; higher Ka means a stronger acid. pKa is related to Ka by the formula pKa = −log Ka , so a lower pKa corresponds to a higher Ka. Thus, lower pKa → stronger acid, higher pKa → weaker acid.

Correct answer: Both "Higher pKa , weaker the acid" & "Lower pKa , stronger the acid"

47. Which of the following solutions has a pH of zero?

  • A. 1 M HCl
  • B. 1 M HF
  • C. 1 M HNO₃
  • D. 1 M CH₃COOH

Explanation: A pH of zero corresponds to a hydrogen ion concentration of [H⁺] = 10⁰ = 1 M. Since HCl is a strong acid, a 1 M HCl solution will fully dissociate to produce a [H⁺] of 1 M.

Correct answer: 1 M HCl

48. The pH of a solution is 5. The hydroxyl ion concentration in mol·dm⁻³ is:

  • A. 10⁻⁵
  • B. 10⁻⁹
  • C. 10⁵⋅⁵
  • D. 10⁻⁷

Explanation: The relationship between pH and pOH is pH + pOH = 14. If the pH is 5, the pOH is 14 - 5 = 9. The hydroxyl ion concentration is [OH⁻] = 10⁻pOH = 10⁻⁹ M.

Correct answer: 10⁻⁹

49. Which is correct about a 1.0 × 10⁻³ M HCl solution & a 1.0 × 10⁻⁵ M HClO₄ solution?

  • A. The HCl solution is less acidic than the HClO₄ solution
  • B. The HCl solution is 100 times more acidic than the HClO₄ solution
  • C. The HClO₄ solution is 100 times more acidic than the HCl solution
  • D. None of these

Explanation: Acidity is determined by the H⁺ concentration. Since both are strong acids, the [H⁺] is equal to their molarity. The ratio of concentrations is (1.0 × 10⁻³) / (1.0 × 10⁻⁵) = 100. Thus, the HCl solution is 100 times more concentrated in H⁺ and more acidic.

Correct answer: The HCl solution is 100 times more acidic than the HClO₄ solution

50. The pH of an aqueous solution is 5.5. The hydroxyl ion concentration in the solution will be:

  • A. 10⁻⁸·⁵
  • B. 10⁸⋅⁵
  • C. 8.5
  • D. -8.5

Explanation: The pOH of the solution is 14 - pH = 14 - 5.5 = 8.5. The hydroxyl ion concentration is given by [OH⁻] = 10⁻pOH. Therefore, [OH⁻] = 10⁻⁸.⁵ M.

Correct answer: 10⁻⁸·⁵