When the momentum of body is increased by 200%, its kinetic energy increases by:
Correct answer: D. 800 %
- A. 200 %
- B. 300 %
- C. 400 %
- D. 800 %
Explanation
Momentum P = mv Kinetic energy K.E= 1 /2 mv^2 K.E= p^2/ 2mIf p is increased vy 200% ,then new p will be. p*= p+ 200%p p* = p+2pp* = 3pIn this case, new K.E will be, K.E* = p*^2 / 2m = [3p]^2 /2m = 9p^2/ 2m K.E*= 9 K.E [as, p^2/ 2m= K.E]ΔK.E% [ percent change in K.E] = K.E* -K.E = 9 K.E - K.E = 8 *100% ΔK.E% = 800%
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About Kinetic Energy
Kinetic energy is the energy of motion, given for a nonrelativistic object by K = ½mv², so it depends on mass and the square of speed. Questions connect kinetic energy with work through the work energy theorem, calculate changes in kinetic energy, and distinguish it from momentum and potential energy.
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