When 2-Bromo-2-methyl propane undergoes unimolecular elimination reaction, the product obtained will be:
Correct answer: B. 2-Methyl propene
- A. 2-Methyl propane
- B. 2-Methyl propene
- C. 2-Methyl-1 propanol
- D. 2-pentanol
Explanation
The unimolecular elimination (E1) reaction of 2-Bromo-2-methyl propane involves the removal of the bromine atom, resulting in the formation of a carbocation. This intermediate then undergoes rearrangement to form the most stable alkene, which in this case is 2-Methyl propene, an alkene with a double bond.Option A, 2-Methyl propane, is incorrect because the elimination reaction leads to an alkene, not an alkane. Option C, 2-Methyl-1 propanol, is incorrect because no alcohol is formed in this type of reaction. Option D, 2-pentanol, is incorrect because the starting material does not have the carbon chain length necessary to form 2-pentanol.
This question appeared on the ETEA MDCAT 2013 paper, which you can sit online with every answer explained.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Elimination Reactions
Elimination reactions remove a leaving group and a hydrogen atom from adjacent carbon atoms to form an alkene. The topic covers dehydrohalogenation of alkyl halides, E1 and E2 mechanisms, the role of base, solvent and substrate structure, and Zaitsev orientation, which is often contrasted with substitution.
Practise Alkyl Halides
458 free Alkyl Halides MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Elimination Reactions questions
Dehydrahalogenation·of alkyl halide·is carried with:
Identify the correct statement related to substitution and elimination of alkyt halides:
In the elimination reaction, alcoholic KOH is used. OH- in this case, will act as:
KOH (alcoholic) + CH3 (CH3) 2 CH2Br (1), The reactants in the condition given will undergo:
Dehydrohalogenation of alkylhalide is carried out in presence of:
Greater number of Alkyl groups on substrate favours: