Two tuning forks produces N beats. If one of these tuning forks has the frequency f, then the frequency of the other would be:
Correct answer: D. N+f
- A. N-f
- B. N/f
- C. N*f
- D. N+f
Explanation
When two tuning forks with slightly different frequencies are sounded together, they produce beats, which are periodic variations in sound intensity. The number of beats per second is equal to the difference in frequency between the two tuning forks. Let's assume the frequency of one tuning fork is f. The other tuning fork must have a frequency that is different by N from the first tuning fork. Therefore, the frequency of the other tuning fork would be f+N. Hence, the correct answer is N+f.
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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