The volume occupied by 1.4g of N2 at S.T.P is:

Explanation

To determine the volume occupied by 1.4g of N2 at standard temperature and pressure (STP), we need to use the ideal gas law equation: PV = nRT Where: P = pressure (in atm) V = volume (in dm3) n = number of moles of gas R = ideal gas constant (0.0821 dm3.atm/mol.K) T = temperature (in Kelvin) At STP, the pressure (P) is 1 atm, and the temperature (T) is 273.15 K (0 degrees Celsius) Now, we need to calculate the number of moles of N2 .The molar mass of N2 (nitrogen gas) is: = 2 * molar mass of nitrogen (N) = 2 * 14.01 g/mol = 28.02 g/mol Number of moles of N2= Mass of N2 / Molar mass of N2 Number of moles of N2 = 1.4 g / 28.02 g/mol ≈ 0.05 mol Now, we can use the ideal gas law to find the volume (V) occupied by 0.05 moles of N2 at STP: V = nRT / P V = (0.05 mol) * (0.0821)* (273.15 K) / (1 atm) V ≈ 1.12 dm3