The kinetic energy of a simple harmonic oscillator is double of its potential energy at a point where instantaneous displacement is equal to:
Correct answer: C. 1/√3 (amplitude)
- A. 1/2 (amplitude)
- B. 1/√2 (amplitude)
- C. 1/√3 (amplitude)
- D. None
Explanation
In a simple harmonic oscillator, the kinetic energy (KE) is equal to half the potential energy (PE) at any given point. Therefore, when the kinetic energy is double the potential energy, it implies that K.E = 2P.E. This condition is satisfied when the instantaneous displacement is equal to 1/√3 (amplitude) of the oscillation.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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