The Incorrect statement among the following is: (lonization Energy = I.E.)
Correct answer: B. The second I.E. of Mg is greater than the second I.E. of Na
- A. The first I.E. of Al is less than the first I.E. of Mg
- B. The second I.E. of Mg is greater than the second I.E. of Na
- C. The first I.E. of Na is less than the first I.E. of Mg
- D. The third I.E of Mg is greater than the third I.E. of Al
Explanation
Option B Is correct.That is not correct. The second ionization energy (IE) of sodium is greater than the second IE of magnesium.The first ionization energy is the energy required to remove the most loosely bound electron from an atom in its ground state. The second ionization energy is the energy required to remove a second electron from an atom that has already lost one electron. In the case of sodium and magnesium, the first ionization energy is lower for sodium than for magnesium. This is because sodium has a larger atomic radius than magnesium. The valence electrons in sodium are therefore further away from the nucleus and are less attracted to it.However, the second ionization energy is lower for sodium than for magnesium. This is because after sodium loses one electron, it has a filled 2p subshell. The valence electrons in magnesium are still in the 3s subshell, which is not filled. The magnesium atom is therefore more stable with two electrons in the 3s subshell than with only one electron. The higher second ionization energy of sodium makes it less reactive than magnesium. This is because sodium is less easily able to lose a second electron and form a doubly positive ion. Magnesium is more reactive because it is more easily able to lose two electrons and form a doubly positive ion.
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