The frequency of a light beam "A" is half of that of light beam "B". The ratio EA/Ea of photons energies is:(hint: where EA & Es are the respective energies of light Beam "A" & "B")
Correct answer: A. 1/2
- A. 1/2
- B. 1/4
- C. 1
- D. 2
Explanation
The correct answer is 1/2. The energy of a photon can be calculated using the formula E = hf, where E is energy, h is Planck's constant, and f is frequency. If the frequency of light beam 'A' is half that of light beam 'B' (i.e., fA = 1/2 * fB), we can express the energies of the two beams as EA = h * fA and EB = h * fB. Substituting for fA gives us EA = h * (1/2 * fB) = (1/2) * h * fB = (1/2) * EB. Thus, the ratio EA/EB = (1/2) and is equal to 1/2. The other options are incorrect for the following reasons: - 1/4: This implies a larger difference in energy than the frequency relationship allows. - 1: This suggests equal energies, which contradicts the stated frequency relationship. - 2: This incorrectly suggests that beam 'A' has higher energy, which is not possible given its lower frequency.
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Light is studied through reflection, refraction, dispersion, interference, diffraction and polarization, linking ray behavior with its wave nature. Questions may involve mirrors, lenses, optical instruments, refractive index and image formation, while geometrical optics deals with rays and wave optics explains effects such as interference and diffraction.
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