The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds. The number of revolutions made during that time is
Correct answer: D. 2000
- A. 600
- B. 1500
- C. 1000
- D. 2000
Explanation
The angular acceleration of the wheel is α=Δω/Δt =300rps/10s −10rps =20rps^2. Now, using the formula θ=ωi t+21 αt2, where θ is the total angle traversed, ωi is the initial angular velocity, α is the angular acceleration, and t is the time, we can find θ=(100rps×10s)+1/2 ×20rps2×(10s)^2=2000
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About Angular Displacement
Angular displacement measures the change in a body’s angular position and is expressed in radians or degrees, with anticlockwise and clockwise directions assigned signs. It connects to arc length, angular velocity and angular acceleration, and must be distinguished from ordinary linear displacement in rotational motion.
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