Solubility product of AgCl is 2.0 x 10^-10 mol2 dm-6. Maximum Concentration of Ag+1 ions in the solution is__________________?

Correct answer: B. 1.414 x 10^-5 mol dm-3

  • A. 2.0 x 10^-10 mol dm-3
  • B. 1.414 x 10^-5 mol dm-3
  • C. 1.0 x 10^-10 mol dm-3
  • D. 1.0 x 10^-5 mol dm-3

Explanation

For AgCl(s) ⇌ Ag+ + Cl-, if the solubility is s mol dm-3, then [Ag+] = [Cl-] = s and Ksp = s2. Therefore s = square root of 2.0 x 10^-10 mol2 dm-6 = 1.414 x 10^-5 mol dm-3. The common mistake is choosing 2.0 x 10^-10 mol dm-3 by treating Ksp itself as the ion concentration.

Written and checked by , M.Phil ChemistryLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Solubility Product

The solubility product constant, Ksp, represents the equilibrium concentrations of ions from a sparingly soluble salt, each raised to its stoichiometric power. Problems involve writing Ksp expressions, calculating molar solubility, applying the common-ion effect and predicting precipitation from the ionic product.

Practise Chemical Equilibrium

626 free Chemical Equilibrium MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Chemistry questions like this

Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Solubility Product questions