Regarding color blindness when a normal male marries a carrier female, which is the correct statement?

Explanation

In this genetic scenario, the mother is a carrier of the color blindness allele, with a genotype of XhX, and the father is normal with a genotype of XY. Daughters inherit one X chromosome from each parent, meaning they will receive a normal X chromosome from the father and either a carrier or a normal X chromosome from the mother. Thus, daughters cannot be color blind unless both parents pass on the color blindness allele, which is not possible here. Sons inherit the Y chromosome from the father and one X chromosome from the mother. Since the mother is a carrier, there is a 50% chance that sons will inherit the X chromosome with the color blindness allele, leading to half of the sons being color blind. The remaining sons will inherit the normal X chromosome and will not be color blind. Therefore, Option D is correct.