Reducing mass M of a suspending body to one fourth will change the frequency of oscillation to:
Correct answer: B. Double
- A. One fourth
- B. Double
- C. Quardruple
- D. Half
Explanation
The relationship between the frequency and the mass of an object undergoing simple harmonic motion can be expressed as: f = 1 / √M When the mass is reduced to one fourth (M/4), the frequency can be calculated as: f ' = f √(M/4) f ' = f (√M) / 2 Therefore, the frequency is doubled when the mass is reduced to one fourth.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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