One proton beam enters a magnetic field of 10-4T normally, a specific charge of 1011C/kg, and a velocity of 107m/s. What is the radius of the circle described by it?
Correct answer: B. 1 m
- A. 0.1 cm
- B. 1 m
- C. 10 cm
- D. None of these
Explanation
The radius of the circle described by a charged particle moving perpendicular to a magnetic field is given by the formula:r = mv/(qB), where:m is the mass of the particle, q is the charge, v is the velocity, and B is the magnetic field strength.For a proton, the specific charge q/m is given as 1011 C/kg. Using the provided velocity v = 107 m/s and magnetic field strength B = 10-4 T:r = v/(q/m × B) = 107 / (1011 × 10-4) = 1 mThus, the correct answer is Option B: 1 m. Options A and C result from calculation errors or incorrect unit conversions. Option D is incorrect because a correct answer is provided in the options.
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