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n an LCR series circuit, if V is the effective value of the applied voltage VR is the voltage across R VL is the effective voltage across L & Vc is the effective voltage across C then_______________?

Correct answer: C. V2 = VR2+(VL-VC)2

  • A. IA. V = VR+VL+VC
  • B. V2 = VR2+VL2+VC2
  • C. V2 = VR2+(VL-VC)2
  • D. V2 = VL2+(VR-VC)2

Explanation

In a series LCR circuit, VR is in phase with the current, while VL and VC are 90° from it and opposite to each other. Therefore the effective supply voltage satisfies V² = VR² + (VL - VC)², with every voltage measured in volts. Students may choose a by adding all voltage magnitudes directly and ignoring their phase relationships.

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