Lactose commonly used as a binder in tablets has a molecular weight of 342. What weight of CO2 would be formed when 1/12 mole of this compound is burnt completely?(C12H22O11 + 12O2 12CO2 + 11H2O)

Explanation

The balanced equation is: C12H22O11 + 12O2 → 12CO2 + 11H2O From the balanced equation, we can see that the molar ratio between lactose (C12H22O11) and CO2 is 1:12, meaning that 1 mole of lactose reacts to form 12 moles of CO2. First, let's determine the number of moles of lactose: Molar mass of lactose (C12H22O11) = 12(12.01 g/mol) + 22(1.01 g/mol) + 11(16.00 g/mol) = 342.34 g/mol Moles of lactose = 1/12 mole (given) Since the molar ratio between lactose and CO2 is 1:12, we can conclude that 1/12 mole of lactose will produce 12/12 = 1 mole of CO2. Now, let's calculate the weight of CO2: Molar mass of CO2 = 12.01 g/mol (carbon) + 16.00 g/mol (oxygen) + 16.00 g/mol (oxygen) = 44.01 g/mol Weight of CO2 = moles of CO2 × molar mass of CO2 = 1 mole × 44.01 g/mol = 44.01 g Thus, the weight of carbon dioxide (CO2) formed when 1/12 mole of lactose is completely burnt is 44.01 grams. Therefore, the correct answer is 44 g.