In a stationary wave, the distance between adjacent antinodes is equal to:
Correct answer: C. λ/2
- A. λ
- B. 2λ
- C. λ/2
- D. λ/4
Explanation
An antinode is the point of max displacement, and antinodes are separated by nodes, point of minimal displacement. This separation is constant and the length between a node and antinode is λ/4 so the distance between adjacent antinodes would be λ/2. In a stationary wave, the distance between adjacent nodes (points with zero amplitude) is half of the wavelength (λ/2).A stationary wave is formed by the superposition of two waves with the same frequency and amplitude traveling in opposite directions. The points where the amplitude of the wave is zero are called nodes, and the points where the amplitude is maximum are called antinodes.In a stationary wave, the distance between adjacent nodes can be calculated as:distance between adjacent nodes = λ/2where λ is the wavelength of the wave. Therefore, the distance between adjacent nodes depends on the wavelength of the wave.
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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