If the temperature of an ideal gas in a sealed, rigid container is increased to 1.5 times the initial value (in K), the density of gas:
Correct answer: D. Remains the same
- A. Becomes 1.5 times the initial value
- B. Becomes 1/1.5 times the initial value
- C. Becomes 2.25 times the initial value
- D. Remains the same
Explanation
According to the formula and reference given below density should decrease. By increasing the temperature from 0°C to 27°C the density of gas has decreased from 0.7138 g dm-3 to 0.649 g dm-3. The increase of temperature makes the molecules of a gas to move away from each other. d= PM/RT d= m/V BUT for a sealed rigid container mass as well as volume remains a constant hence the density remains same at the temperature changes.
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About Ideal Gas Equation
The ideal gas equation, PV = nRT, relates pressure, volume, amount and absolute temperature when gas particles are assumed to have negligible volume and no intermolecular forces. Applications include finding molar mass, density or an unknown gas variable, with careful use of Kelvin temperature and consistent units, and comparison with real-gas behaviour.
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