If the radioactive decay constant of radium is 1.07 x 10^-4 per year, then its half-life period is approximately equal to:
Correct answer: B. 6,476 years
- A. 8,900 years
- B. 6,476 years
- C. 7,000 years
- D. 2,520 years
Explanation
The half-life of a radioactive element is given by the following formula: T1/2 = ln(2) / λ where T1/2 is the half-life, ln(2) is the natural logarithm of 2, and λ is the decay constant. In this case, the decay constant is given as 1.07 x 10-4 per year. So, the half-life of radium is: T1/2 = ln(2) / 1.07 x 10-4 = 6,476 years.
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About Half-life and Rate of Decay
Half-life is the time required for half the unstable nuclei in a sample to decay, and it remains constant for a particular radioactive nuclide. Questions use the exponential decay law, decay constant, activity, remaining quantity and mean life. Radioactive decay is random for individual nuclei but predictable for large samples.
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