If the period of oscillation of mass (M) suspended from a spring is 2s,then the period of mass 4M will be:

Explanation

The formula for the period of a mass-spring system is: T = 2π √(m/k) Where: T is the period of oscillation, m is the mass of the object, and k is the spring constant. In this case, we have a mass M with a period of 2 seconds. So, we can substitute these values into the formula: 2 = 2π √(M/k) Now, let's consider the mass 4M. We need to find the new period, let's call it T'. So, we have: T' = 2π √((4M)/k) To compare the periods, we can divide the two equations: T' / T = (2π √((4M)/k)) / (2π √(M/k)) Simplifying this equation, we get: T' / T = √((4M)/k) / √(M/k) T' / T = √(4M) / √M T' / T = 2√M / √M T' / T = 2 Therefore, the period of a mass 4M will be twice the period of a mass M. Since the period of M is 2 seconds, the period of 4M will be 2 * 2 = 4 seconds. So, the correct option is (d) 4s.