How many moles of Calcium Carbonate are present in 1.75 kg of Calcium Carbonate? (Ar of Ca = 40, Ar of C = 12, Ar of O = 16)
Correct answer: D. 17.5 mol
- A. 1.75 mol
- B. 1750 mol
- C. 0.0175 mol
- D. 17.5 mol
Explanation
The molar mass of CaCO3 (40 + 12 + 16 + 16 + 16) is 100g per mole. If one mole equals 100g, than 1750g (1.75 kg x 1000) equals 1750/100, which is 17.5 mol so, D is the answer.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
Practise Fundamental Concepts of Chemistry
894 free Fundamental Concepts of Chemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Fundamental Concepts of Chemistry questions
During stoichiometric calculations, which of the following laws must be followed?
The unit _ is commonly used by meteorologist:
The term which shows the quantitative relationship between the products and reactants is called as_?
The number of moles of water in 1 kg ice are:
Solution contains 85.5g of sucrose (C12H22O11) in 250 cm3. What is its molarity?
The relative atomic mass of copper is?