For two gases A and B with molecular weights MA and MB , it is observed that at a certain temperature T1 the mean velocity of A is equal to the root mean square velocity of B. Thus, the mean velocity of A can be made equal to the mean velocity of B if:
Correct answer: B. A is lowered to a temperature T2,T2< T while B is at T
- A. A is at temperature T and B at T',T', T'
- B. A is lowered to a temperature T2,T2< T while B is at T
- C. Both A and B are raised to a higher temperature
- D. Both A and B are placed at lower temperature
Explanation
For two gases A and B with molecular weights MA and MB, it is observed that at a certain temperature T1, the mean velocity of A is equal to the root mean square velocity of B. Thus, the mean velocity of A can be made equal to the mean velocity of B if both A and B are raised to a lower temperature. This is the following solution:
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About Kinetic Molecular Theory
Kinetic molecular theory explains gases as rapidly moving particles separated by large distances, with negligible volume and negligible intermolecular attraction in the ideal model. It relates temperature to average kinetic energy and explains gas pressure, Boyle's and Charles's laws, diffusion, effusion and the conditions under which real gases deviate from ideal behavior.
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