Asked in ETEA MDCAT 2017 2017Moderate

At standard conditions 45 liters of oxygen gas weight about 64 g, where as 45 liters of hydrogen weight only 4g. Which gas defuse faster ? Calculate how much faster.

Correct answer: B. Hydrogen, 2O2

  • A. Hydrogen, 4O2
  • B. Hydrogen, 2O2
  • C. Oxygen, 8H2
  • D. Oxygen, 3H2

Explanation

The balanced chemical equation for the reaction between oxygen gas and hydrogen gas is:O2 + 4H2 → 2H2OAccording to this equation, for every 1 mole of oxygen gas, 4 moles of hydrogen gas are consumed. Therefore, to compare the diffusion rates of oxygen gas and hydrogen gas in this reaction, we need to compare the rates of diffusion of 1 mole of oxygen gas with the rates of diffusion of 4 moles of hydrogen gas.The ratio of the rates of diffusion of 1 mole of oxygen gas to 4 moles of hydrogen gas is:Rate of diffusion(O2) / Rate of diffusion(4H2) = 1 / (4√(M(H2) / M(O2))) = 1 / (4√(2 g/mol / 32 g/mol)) = 1 / (4√(1/16)) = 1 / This means that oxygen gas will diffuse 2 times slower than 4 moles of hydrogen gas. Alternatively, we can express this ratio in terms of the number of molecules:Rate of diffusion(O2) / Rate of diffusion(8H2) = √(n(8H2) / n(O2)) = √(8 x 2 mol / 2 mol) = √(8) = 2.83This indicates that 8 moles of hydrogen gas will diffuse 2.83 times faster than 1 mole of oxygen gas. Therefore, the correct answer to the question is option B) Hydrogen, 4O2.

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About Kinetic Molecular Theory

Kinetic molecular theory explains gases as rapidly moving particles separated by large distances, with negligible volume and negligible intermolecular attraction in the ideal model. It relates temperature to average kinetic energy and explains gas pressure, Boyle's and Charles's laws, diffusion, effusion and the conditions under which real gases deviate from ideal behavior.

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