At 1489 mm of Hg, water will boil at:
Correct answer: A. 120 oC
- A. 120 oC
- B. 110 oC
- C. 100 oC
- D. 90 oC
Explanation
At a pressure of 1489 mmHg (millimeters of mercury), water will boil at approximately 120 degrees Celsius (212 degrees Fahrenheit). The boiling point of a substance, such as water, depends on the pressure applied to it. Under normal atmospheric pressure at sea level, which is around 760 mmHg, water boils at 100 degrees Celsius (212 degrees Fahrenheit). However, when the pressure is increased, as in the case of 1489 mmHg, the boiling point of water also increases. At higher pressures, the boiling point of water increases because the additional pressure on the water molecules raises the energy required for them to overcome the intermolecular forces and transition from the liquid phase to the gaseous phase (vaporization). This results in an increase in the boiling point temperature. It's important to note that the boiling point of water can vary with altitude and atmospheric conditions, as the atmospheric pressure changes with elevation. Additionally, impurities and dissolved substances in the water can also affect its boiling point. The value mentioned above (100 degrees Celsius at 1489 mmHg) is an approximate estimation based on the relationship between pressure and boiling point. Although you are not expected to know the calculation of boiling points at various pressures, you must understand that at pressures higher than atmospheric pressure, the boiling point must also be higher than that at atmospheric pressure. This is because the boiling point is defined as the temperature at which the vapor pressure equals the external pressure. So, the higher the pressure, the higher the required temperature to evaporate enough liquid to equal the external pressure. Since 1489 mm of Hg>760 mm of Hg(atmospheric pressure), the boiling point must also be greater than 100. The best option in this case is, therefore, option A. If you have read the book thoroughly, this may just be a factual recall for you:
Last updated
About Evaporation, Boiling Point and Vapour Pressure
Evaporation is the escape of higher-energy molecules from a liquid surface, while vapour pressure is the pressure exerted by vapour in equilibrium with that liquid. The topic distinguishes evaporation from boiling and relates both to temperature, intermolecular forces, surface area, atmospheric pressure and the boiling point.
Practise Liquids
350 free Liquids MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
18g glucose is dissolved in 90g water the relative lowering in vapour pressure is equal to ___________________?
A jar contains a gas and a few drops of water at 'T' Kelvin temperature. The pressure in the jar is 830 mm of Hg. The temperature of the jar is reduced by 1%. The vapour pressure of water at two temperatures are 30 and 25 mm of Hg respectively. Calculate the new pressure in the jar?
A liquid boils when its vapour pressure becomes equal to
A pressure cooker cooks food faster because increasing the pressure inside
A pressure cooker works on which principle?