An organic compound has the empirical formula C3H3O if the molar mass of the compound is 110.15 gmol-1. The molecular formula of this organic compound is: (A, of C=12, H=1.008and O=16)
Correct answer: A. C6H6O2
- A. C6H6O2
- B. C3H3O
- C. C9H9O3
- D. C6H6O3
Explanation
The empirical formula mass can be calculated as follows:Empirical formula mass = (3 x atomic mass of C) + (3 x atomic mass of H) + (1 x atomic mass of O) Empirical formula mass = (3 x 12.011) + (3 x 1.008) + 16.00 Empirical formula mass = 55.05 g/molThe molecular formula mass can be calculated using the following equation:Molecular formula mass = n x empirical formula masswhere n is the number of empirical formula units in the molecular formula.n can be calculated as follows:n = Molecular formula mass / Empirical formula massn = 110.15 / 55.05 n = 2Therefore, the molecular formula is 2 times the empirical formula, and the molecular formula is:2(C3H3O) = C6H6O2So, the correct option is A) C6H6O2.
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